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Find the break even points of the polynomial $\left(-2-x\right)^2\left(-2-x\right)$ by putting it in the form of an equation and then set it equal to zero
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$\left(-2-x\right)^2\left(-2-x\right)=0$
Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression (-2-x)^2(-2-x). Find the break even points of the polynomial \left(-2-x\right)^2\left(-2-x\right) by putting it in the form of an equation and then set it equal to zero. When multiplying exponents with same base you can add the exponents: \left(-2-x\right)^2\left(-2-x\right). Removing the variable's exponent raising both sides of the equation to the power of \frac{1}{3}. We need to isolate the dependent variable , we can do that by simultaneously subtracting -2 from both sides of the equation.