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$\int\left(\sqrt{2xp-\sqrt{3zq}}\right)^2dx$
Learn how to solve integral calculus problems step by step online. Integrate the function (2xp-(3zq)^1/2)^1/2^2. Find the integral. Simplify the expression inside the integral. The integral \int2xpdx results in: px^2. The integral \int-\sqrt{3zq}dx results in: -\sqrt{3}\sqrt{zq}x.