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Find the break even points of the polynomial $1\cdot -4\left(x^3-3x^2+5x-6\right)x^2$ by putting it in the form of an equation and then set it equal to zero
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$1\cdot -4\left(x^3-3x^2+5x-6\right)x^2=0$
Learn how to solve integral calculus problems step by step online. Find the break even points of the expression (x^3-3x^25x+-6)1*-4x^2. Find the break even points of the polynomial 1\cdot -4\left(x^3-3x^2+5x-6\right)x^2 by putting it in the form of an equation and then set it equal to zero. Multiply 1 times -4. We can factor the polynomial \left(x^3-3x^2+5x-6\right) using the rational root theorem, which guarantees that for a polynomial of the form a_nx^n+a_{n-1}x^{n-1}+\dots+a_0 there is a rational root of the form \pm\frac{p}{q}, where p belongs to the divisors of the constant term a_0, and q belongs to the divisors of the leading coefficient a_n. List all divisors p of the constant term a_0, which equals -6. Next, list all divisors of the leading coefficient a_n, which equals 1.