Final Answer
$\left(\sqrt[3]{x^{2}}+2x+1\right)^2\sqrt[5]{x^2-2}$
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Step-by-step Solution
Specify the solving method
1
Simplify $\sqrt[3]{x^2}$ using the power of a power property: $\left(a^m\right)^n=a^{m\cdot n}$. In the expression, $m$ equals $2$ and $n$ equals $\frac{1}{3}$
$\left(x^{2\frac{1}{3}}+2x+1\right)^2\sqrt[5]{x^2-2}$
2
Multiply $2$ times $\frac{1}{3}$
$\left(\sqrt[3]{x^{2}}+2x+1\right)^2\sqrt[5]{x^2-2}$
Final Answer
$\left(\sqrt[3]{x^{2}}+2x+1\right)^2\sqrt[5]{x^2-2}$