$\frac{d}{dx}\left(\sqrt[3]{\left(\frac{1}{4}x^4-4\right)^3-x^3}\right)=\frac{3\left(\frac{1}{4}x^4-4\right)^{2}x^{3}-3x^{2}}{3\sqrt[3]{\left(\left(\frac{1}{4}x^4-4\right)^3-x^3\right)^{2}}}$
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