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$\int\frac{x^3-8}{x-2}dx$
Learn how to solve integral calculus problems step by step online. Integrate the function (x^3-8)/(x-2). Find the integral. Rewrite the expression \frac{x^3-8}{x-2} inside the integral in factored form. Expand the integral \int\left(3+\left(x+1\right)^2\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int3dx results in: 3x.