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Solve the product $\left(\frac{5}{1}-\frac{1}{4}\right)\cdot \left(\frac{5}{1}-\frac{1}{4}\right)$

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 Solution

 Videos

Algebra 2 - Learning to solve rational equations in math class ((x+3)/(x‐2)) + (5/(x^2‐4)) = 1

https://www.youtube.com/watch?v=y8p0Tpn3BcI

Algebra 2 - Solving a factored quadratic equation using the zero product property, -x(3x + 5) = 0

https://www.youtube.com/watch?v=3on6rsKoK_k

Pre-Calculus - Mulitplying by the LCM to simplify a complex fraction, (1/4 + 2/3)/(5/6 - 1/12)

https://www.youtube.com/watch?v=Cz-Gq4tqQ6c

Calculus - Solving Rational Equations, ((4x + 1)/4) - ((2x + 3)/3) = 7/12

https://www.youtube.com/watch?v=1J6QI7lmlj4

Equations with rational expressions | Mathematics III | High School Math | Khan Academy

https://www.youtube.com/watch?v=McOMtxI_Jzs

Algebra 2 - Multiplying two exponents with rational powers, then simplifying, 2x^(2/5) . 6x^(1/4)

https://www.youtube.com/watch?v=ITQM50h5BlY

 Function Plot

Plotting: $\frac{361}{16}$

SnapXam A²

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1

2

3

4

5

6

7

8

9

0



a

b

c

d

f

g

m

n

u

v

w

x

y

z

.

(◻)

+

-

×

◻/◻

/

÷

◻²

◻^◻

√◻

√

^◻√◻

^◻√

∞

e

π

ln

log

log_◻

lim

d/dx

D^□_x

∫

∫^◻

|◻|

θ

=

>

<

>=

<=

sin

cos

tan

cot

sec

csc

asin

acos

atan

acot

asec

acsc

sinh

cosh

tanh

coth

sech

csch

asinh

acosh

atanh

acoth

asech

acsch

 How to improve your answer:

Main Topic: Special Products

Special products is the multiplication of algebraic expressions that follow certain rules and patterns, so you can predict the result without necessarily doing the multiplication.

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