Final answer to the problem
Step-by-step Solution
Specify the solving method
Factor the trinomial $y^2-2y-3$ finding two numbers that multiply to form $-3$ and added form $-2$
Learn how to solve integral calculus problems step by step online.
$\begin{matrix}\left(1\right)\left(-3\right)=-3\\ \left(1\right)+\left(-3\right)=-2\end{matrix}$
Learn how to solve integral calculus problems step by step online. Integrate the function y/(y^2-2y+-3) from 4 to 8. Factor the trinomial y^2-2y-3 finding two numbers that multiply to form -3 and added form -2. Thus. Rewrite the fraction \frac{y}{\left(y+1\right)\left(y-3\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(y+1\right)\left(y-3\right).