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The integral $\int_{0}^{4}3dx$ results in: $12$
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$12$
Learn how to solve integral calculus problems step by step online. Find the integral int(3)dx&0&4+-int(1/4(x^2-4x+4))dx&0&4. The integral \int_{0}^{4}3dx results in: 12. The integral -\int_{0}^{4}\frac{1}{4}\left(x^2-4x+4\right)dx results in: -\frac{4}{3}. Gather the results of all integrals. Subtract the values 12 and -\frac{4}{3}.