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Since the integral $\int_{0}^{3}\frac{1}{x^2-6x+5}dx$ has a discontinuity inside the interval, we have to split it in two integrals
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$\int_{0}^{1}\frac{1}{x^2-6x+5}dx+\int_{1}^{3}\frac{1}{x^2-6x+5}dx$
Learn how to solve integral calculus problems step by step online. Integrate the function 1/(x^2-6x+5) from 0 to 3. Since the integral \int_{0}^{3}\frac{1}{x^2-6x+5}dx has a discontinuity inside the interval, we have to split it in two integrals. The integral \int_{0}^{1}\frac{1}{x^2-6x+5}dx results in: undefined. The integral \int_{1}^{3}\frac{1}{x^2-6x+5}dx results in: undefined. Gather the results of all integrals.