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Factor the trinomial $x^2-5x+6$ finding two numbers that multiply to form $6$ and added form $-5$
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$\begin{matrix}\left(-2\right)\left(-3\right)=6\\ \left(-2\right)+\left(-3\right)=-5\end{matrix}$
Learn how to solve factor problems step by step online. Integrate the function (x-4)/(x^2-5x+6) from 0 to 1. Factor the trinomial x^2-5x+6 finding two numbers that multiply to form 6 and added form -5. Thus. Rewrite the fraction \frac{x-4}{\left(x-2\right)\left(x-3\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(x-2\right)\left(x-3\right).