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Rewrite the expression $\frac{x^3-4x-10}{x^2-x-6}$ inside the integral in factored form
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$\int_{0}^{1}\frac{x^3-4x-10}{\left(x+2\right)\left(x-3\right)}dx$
Learn how to solve definite integrals problems step by step online. Integrate the function (x^3-4x+-10)/(x^2-x+-6) from 0 to 1. Rewrite the expression \frac{x^3-4x-10}{x^2-x-6} inside the integral in factored form. Expand. Divide x^3-4x-10 by x^2-x-6. Resulting polynomial.