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Rewrite the fraction $\frac{y}{y^2-4y-45}$ inside the integral as the product of two functions: $y\frac{1}{y^2-4y-45}$
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$\int_{12}^{15} y\frac{1}{y^2-4y-45}dy$
Learn how to solve definite integrals problems step by step online. Integrate the function y/(y^2-4y+-45) from 12 to 15. Rewrite the fraction \frac{y}{y^2-4y-45} inside the integral as the product of two functions: y\frac{1}{y^2-4y-45}. We can solve the integral \int y\frac{1}{y^2-4y-45}dy by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.