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Expand the integral $\int_{0}^{3}\left(-191+x^2\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{0}^{3}-191dx+\int_{0}^{3} x^2dx$
Learn how to solve definite integrals problems step by step online. Integrate the function -191+x^2 from 0 to 3. Expand the integral \int_{0}^{3}\left(-191+x^2\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{3}-191dx results in: -573. The integral \int_{0}^{3} x^2dx results in: 9. Gather the results of all integrals.