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Expand the integral $\int_{0}^{2}\left(x^2-2x\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{0}^{2} x^2dx+\int_{0}^{2}-2xdx$
Learn how to solve definite integrals problems step by step online. Integrate the function x^2-2x from 0 to 2. Expand the integral \int_{0}^{2}\left(x^2-2x\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{0}^{2} x^2dx results in: \frac{8}{3}. The integral \int_{0}^{2}-2xdx results in: -4. Gather the results of all integrals.