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Integrate the function $\frac{x-1}{x+1}$ from 0 to $1$

Step-by-step Solution

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Final answer to the problem

$-1.0794415+x\ln\left(x+1\right)$
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Step-by-step Solution

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Expand the fraction $\frac{x-1}{x+1}$ into $2$ simpler fractions with common denominator $x+1$

$\int_{0}^{1}\left(\frac{x}{x+1}+\frac{-1}{x+1}\right)dx$

Learn how to solve definite integrals problems step by step online.

$\int_{0}^{1}\left(\frac{x}{x+1}+\frac{-1}{x+1}\right)dx$

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Learn how to solve definite integrals problems step by step online. Integrate the function (x-1)/(x+1) from 0 to 1. Expand the fraction \frac{x-1}{x+1} into 2 simpler fractions with common denominator x+1. Expand the integral \int_{0}^{1}\left(\frac{x}{x+1}+\frac{-1}{x+1}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. Rewrite the fraction \frac{x}{x+1} inside the integral as the product of two functions: x\frac{1}{x+1}. We can solve the integral \int x\frac{1}{x+1}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula.

Final answer to the problem

$-1.0794415+x\ln\left(x+1\right)$

Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

Solve integral of ((x-1)/(x+1))dx from 0 to 1 using partial fractionsSolve integral of ((x-1)/(x+1))dx from 0 to 1 using basic integralsSolve integral of ((x-1)/(x+1))dx from 0 to 1 using u-substitutionSolve integral of ((x-1)/(x+1))dx from 0 to 1 using trigonometric substitution

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Function Plot

Plotting: $\frac{x-1}{x+1}$

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5
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7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Definite Integrals

Given a function f(x) and the interval [a,b], the definite integral is equal to the area that is bounded by the graph of f(x), the x-axis and the vertical lines x=a and x=b

Used Formulas

4. See formulas

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