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Expand the integral $\int_{-3}^{5}\left(x^4+2yx^2-16x^2+12x-4yx+27-6y\right)dx$ into $7$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{-3}^{5} x^4dx+\int_{-3}^{5}2yx^2dx+\int_{-3}^{5}-16x^2dx+\int_{-3}^{5}12xdx+\int_{-3}^{5}-4yxdx+\int_{-3}^{5}27dx+\int_{-3}^{5}-6ydx$
Learn how to solve definite integrals problems step by step online. Integrate the function x^4+2yx^2-16x^212x-4yx+27-6y from -3 to 5. Expand the integral \int_{-3}^{5}\left(x^4+2yx^2-16x^2+12x-4yx+27-6y\right)dx into 7 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-3}^{5} x^4dx results in: \frac{3368}{5}. The integral \int_{-3}^{5}2yx^2dx results in: \frac{304}{3}y. The integral \int_{-3}^{5}-16x^2dx results in: -\frac{2432}{3}.