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Expand the integral $\int_{-3}^{5}\left(4y^2-2y+3\right)dy$ into $3$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int_{-3}^{5}4y^2dy+\int_{-3}^{5}-2ydy+\int_{-3}^{5}3dy$
Learn how to solve definite integrals problems step by step online. Integrate the function 4y^2-2y+3 from -3 to 5. Expand the integral \int_{-3}^{5}\left(4y^2-2y+3\right)dy into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int_{-3}^{5}4y^2dy results in: \frac{608}{3}. The integral \int_{-3}^{5}-2ydy results in: -16. The integral \int_{-3}^{5}3dy results in: 24.