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Rewrite the expression $\frac{3x^3-24x^2+48x+5}{x^2-8x+16}$ inside the integral in factored form
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$\int_{-3}^{2}\frac{3x^3-24x^2+48x+5}{\left(x-4\right)^{2}}dx$
Learn how to solve problems step by step online. Integrate the function (3x^3-24x^248x+5)/(x^2-8x+16) from -3 to 2. Rewrite the expression \frac{3x^3-24x^2+48x+5}{x^2-8x+16} inside the integral in factored form. Expand. Divide 3x^3-24x^2+48x+5 by x^2-8x+16. Resulting polynomial.