Final Answer
Step-by-step Solution
Specify the solving method
Since the integral $\int_{-2}^{1}\frac{x+2}{2x^2-4x}dx$ has a discontinuity inside the interval, we have to split it in two integrals
Learn how to solve definite integrals problems step by step online.
$\int_{-2}^{0}\frac{x+2}{2x^2-4x}dx+\int_{0}^{1}\frac{x+2}{2x^2-4x}dx$
Learn how to solve definite integrals problems step by step online. Integrate the function (x+2)/(2x^2-4x) from -2 to 1. Since the integral \int_{-2}^{1}\frac{x+2}{2x^2-4x}dx has a discontinuity inside the interval, we have to split it in two integrals. The integral \int_{-2}^{0}\frac{x+2}{2x^2-4x}dx results in: undefined. The integral \int_{0}^{1}\frac{x+2}{2x^2-4x}dx results in: undefined. Gather the results of all integrals.