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Rewrite the fraction $\frac{x}{x^3-3x+2}$ inside the integral as the product of two functions: $x\frac{1}{x^3-3x+2}$
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$\int_{-\frac{1}{2}}^{\frac{1}{2}} x\frac{1}{x^3-3x+2}dx$
Learn how to solve problems step by step online. Integrate the function x/(x^3-3x+2) from -1/2 to 1/2. Rewrite the fraction \frac{x}{x^3-3x+2} inside the integral as the product of two functions: x\frac{1}{x^3-3x+2}. We can solve the integral \int x\frac{1}{x^3-3x+2}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.