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Rewrite the fraction $\frac{x}{\sqrt{x^2}-8}$ inside the integral as the product of two functions: $x\frac{1}{\sqrt{x^2}-8}$
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$\int x\frac{1}{\sqrt{x^2}-8}dx$
Learn how to solve problems step by step online. Find the integral int(x/(x^2^1/2-8))dx. Rewrite the fraction \frac{x}{\sqrt{x^2}-8} inside the integral as the product of two functions: x\frac{1}{\sqrt{x^2}-8}. We can solve the integral \int x\frac{1}{\sqrt{x^2}-8}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.