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Rewrite the fraction $\frac{x^3}{x^2+x-6}$ inside the integral as the product of two functions: $x^3\frac{1}{x^2+x-6}$
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$\int x^3\frac{1}{x^2+x-6}dx$
Learn how to solve problems step by step online. Find the integral int((x^3)/(x^2+x+-6))dx. Rewrite the fraction \frac{x^3}{x^2+x-6} inside the integral as the product of two functions: x^3\frac{1}{x^2+x-6}. We can solve the integral \int x^3\frac{1}{x^2+x-6}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.