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Factor the difference of squares $\left(x^2-4\right)$ as the product of two conjugated binomials
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$\int\frac{x^2+4x-8}{\left(x+2\right)\left(x-1\right)\left(x-2\right)}dx$
Learn how to solve integral calculus problems step by step online. Find the integral int((x^2+4x+-8)/((x^2-4)(x-1)))dx. Factor the difference of squares \left(x^2-4\right) as the product of two conjugated binomials. Rewrite the fraction \frac{x^2+4x-8}{\left(x+2\right)\left(x-1\right)\left(x-2\right)} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by \left(x+2\right)\left(x-1\right)\left(x-2\right). Multiplying polynomials.