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Expand the fraction $\frac{5x+3}{x^2-9}$ into $2$ simpler fractions with common denominator $x^2-9$
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$\int\left(\frac{5x}{x^2-9}+\frac{3}{x^2-9}\right)dx$
Learn how to solve problems step by step online. Find the integral int((5x+3)/(x^2-9))dx. Expand the fraction \frac{5x+3}{x^2-9} into 2 simpler fractions with common denominator x^2-9. Simplify the expression inside the integral. The integral 5\int\frac{x}{x^2-9}dx results in: -5\ln\left(\frac{3}{\sqrt{x^2-9}}\right). The integral \int\frac{3}{x^2-9}dx results in: -\frac{1}{2}\ln\left(x+3\right)+\frac{1}{2}\ln\left(x-3\right).