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Expand the integral $\int\left(\frac{1}{9}\sin\left(3x\right)-\frac{1}{3}x\cos\left(3x\right)\right)dx$ into $2$ integrals using the sum rule for integrals, to then solve each integral separately
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$\int\frac{1}{9}\sin\left(3x\right)dx+\int-\frac{1}{3}x\cos\left(3x\right)dx$
Learn how to solve problems step by step online. Find the integral int(1/9sin(3x)-1/3xcos(3x))dx. Expand the integral \int\left(\frac{1}{9}\sin\left(3x\right)-\frac{1}{3}x\cos\left(3x\right)\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\frac{1}{9}\sin\left(3x\right)dx results in: -\frac{1}{27}\cos\left(3x\right). The integral \int-\frac{1}{3}x\cos\left(3x\right)dx results in: -\frac{1}{9}x\sin\left(3x\right)-\frac{1}{27}\cos\left(3x\right). Gather the results of all integrals.