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Rewrite the fraction $\frac{x-8}{x\left(x^2-4x+4\right)}$ in $2$ simpler fractions using partial fraction decomposition
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$\frac{x-8}{x\left(x^2-4x+4\right)}=\frac{A}{x}+\frac{Bx+C}{x^2-4x+4}$
Learn how to solve problems step by step online. Find the integral int((x-8)/(x(x^2-4x+4)))dx. Rewrite the fraction \frac{x-8}{x\left(x^2-4x+4\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by x\left(x^2-4x+4\right). Multiplying polynomials. Simplifying.