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Expand the fraction $\frac{x-1}{x^2-16}$ into $2$ simpler fractions with common denominator $x^2-16$
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$\int\left(\frac{x}{x^2-16}+\frac{-1}{x^2-16}\right)dx$
Learn how to solve problems step by step online. Find the integral int((x-1)/(x^2-16))dx. Expand the fraction \frac{x-1}{x^2-16} into 2 simpler fractions with common denominator x^2-16. Expand the integral \int\left(\frac{x}{x^2-16}+\frac{-1}{x^2-16}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. Rewrite the fraction \frac{x}{x^2-16} inside the integral as the product of two functions: x\frac{1}{x^2-16}. We can solve the integral \int x\frac{1}{x^2-16}dx by applying integration by parts method to calculate the integral of the product of two functions, using the following formula.