Expand the integral $\int\left(x+1+\frac{-2x+4}{x^4-2x^3+2x^2-2x+1}\right)dx$ into $3$ integrals using the sum rule for integrals, to then solve each integral separately
The integral $\int xdx$ results in: $\frac{1}{2}x^2$
$\frac{1}{2}x^2$
Intermediate steps
5
The integral $\int1dx$ results in: $x$
$x$
Intermediate steps
6
The integral $\int\frac{-2x+4}{x^4-2x^3+2x^2-2x+1}dx$ results in: $\frac{1}{-x+1}-\frac{7}{3}\ln\left(x^{2}+1\right)+\frac{13}{3}\arctan\left(x\right)+8\ln\left(x-1\right)$
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