Final answer to the problem
Step-by-step Solution
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Divide $x^2+3x-4$ by $x^2-2x-8$
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$\begin{array}{l}\phantom{\phantom{;}x^{2}-2x\phantom{;}-8;}{\phantom{;}1\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-2x\phantom{;}-8\overline{\smash{)}\phantom{;}x^{2}+3x\phantom{;}-4\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-2x\phantom{;}-8;}\underline{-x^{2}+2x\phantom{;}+8\phantom{;}\phantom{;}}\\\phantom{-x^{2}+2x\phantom{;}+8\phantom{;}\phantom{;};}\phantom{;}5x\phantom{;}+4\phantom{;}\phantom{;}\\\end{array}$
Learn how to solve problems step by step online. Find the integral int((x^2+3x+-4)/(x^2-2x+-8))dx. Divide x^2+3x-4 by x^2-2x-8. Resulting polynomial. Expand the integral \int\left(1+\frac{5x+4}{x^2-2x-8}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int1dx results in: x.