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Expand the fraction $\frac{x^2+1}{\sqrt[3]{x}}$ into $2$ simpler fractions with common denominator $\sqrt[3]{x}$
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$\int\left(\frac{x^2}{\sqrt[3]{x}}+\frac{1}{\sqrt[3]{x}}\right)dx$
Learn how to solve problems step by step online. Find the integral int((x^2+1)/(x^1/3))dx. Expand the fraction \frac{x^2+1}{\sqrt[3]{x}} into 2 simpler fractions with common denominator \sqrt[3]{x}. Simplify the resulting fractions. Expand the integral \int\left(\sqrt[3]{x^{5}}+\frac{1}{\sqrt[3]{x}}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int\sqrt[3]{x^{5}}dx results in: \frac{3}{8}\sqrt[3]{x^{8}}.