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We could not solve this problem by using the method: Integrate by trigonometric substitution
Cancel exponents $2$ and $\frac{1}{2}$
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$\int\frac{1}{\left(x-1\right)\left(x+1\right)x+x-6}dx$
Learn how to solve problems step by step online. Find the integral int(1/((x-1)(x+1)x^2^1/2+x+-6))dx. Cancel exponents 2 and \frac{1}{2}. The sum of two terms multiplied by their difference is equal to the square of the first term minus the square of the second term. In other words: (a+b)(a-b)=a^2-b^2.. Multiply the single term x by each term of the polynomial \left(x^2-1\right). When multiplying exponents with same base you can add the exponents: x^2x.