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Divide $9x^3+x^2-1$ by $x^2-4$
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$\begin{array}{l}\phantom{\phantom{;}x^{2}-4;}{\phantom{;}9x\phantom{;}+1\phantom{;}\phantom{;}}\\\phantom{;}x^{2}-4\overline{\smash{)}\phantom{;}9x^{3}+x^{2}\phantom{-;x^n}-1\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}-4;}\underline{-9x^{3}\phantom{-;x^n}+36x\phantom{;}\phantom{-;x^n}}\\\phantom{-9x^{3}+36x\phantom{;};}\phantom{;}x^{2}+36x\phantom{;}-1\phantom{;}\phantom{;}\\\phantom{\phantom{;}x^{2}-4-;x^n;}\underline{-x^{2}\phantom{-;x^n}+4\phantom{;}\phantom{;}}\\\phantom{;-x^{2}+4\phantom{;}\phantom{;}-;x^n;}\phantom{;}36x\phantom{;}+3\phantom{;}\phantom{;}\\\end{array}$
Learn how to solve problems step by step online. Find the integral int((9x^3+x^2+-1)/(x^2-4))dx. Divide 9x^3+x^2-1 by x^2-4. Resulting polynomial. Expand the integral \int\left(9x+1+\frac{36x+3}{x^2-4}\right)dx into 3 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int9xdx results in: \frac{9}{2}x^2.