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Rewrite the fraction $\frac{8x+8}{\left(x-1\right)^3\left(x^2+1\right)}$ in $4$ simpler fractions using partial fraction decomposition
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$\frac{8x+8}{\left(x-1\right)^3\left(x^2+1\right)}=\frac{A}{\left(x-1\right)^3}+\frac{Bx+C}{x^2+1}+\frac{D}{x-1}+\frac{F}{\left(x-1\right)^{2}}$
Learn how to solve problems step by step online. Find the integral int((8x+8)/((x-1)^3(x^2+1)))dx. Rewrite the fraction \frac{8x+8}{\left(x-1\right)^3\left(x^2+1\right)} in 4 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C, D, F. The first step is to multiply both sides of the equation from the previous step by \left(x-1\right)^3\left(x^2+1\right). Multiplying polynomials. Simplifying.