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Rewrite the fraction $\frac{6x^2-15x-22}{\left(x+3\right)\left(x^2+1\right)^2}$ in $3$ simpler fractions using partial fraction decomposition
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$\frac{6x^2-15x-22}{\left(x+3\right)\left(x^2+1\right)^2}=\frac{A}{x+3}+\frac{Bx+C}{\left(x^2+1\right)^2}+\frac{Dx+F}{x^2+1}$
Learn how to solve problems step by step online. Find the integral int((6x^2-15x+-22)/((x+3)(x^2+1)^2))dx. Rewrite the fraction \frac{6x^2-15x-22}{\left(x+3\right)\left(x^2+1\right)^2} in 3 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C, D, F. The first step is to multiply both sides of the equation from the previous step by \left(x+3\right)\left(x^2+1\right)^2. Multiplying polynomials. Simplifying.