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Factor the trinomial $x^2-4x+3$ finding two numbers that multiply to form $3$ and added form $-4$
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$\begin{matrix}\left(-1\right)\left(-3\right)=3\\ \left(-1\right)+\left(-3\right)=-4\end{matrix}$
Learn how to solve problems step by step online. Find the integral int(4/(x^2-4x+3))dx. Factor the trinomial x^2-4x+3 finding two numbers that multiply to form 3 and added form -4. Thus. Rewrite the fraction \frac{4}{\left(x-1\right)\left(x-3\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(x-1\right)\left(x-3\right).