Final Answer
Step-by-step Solution
Specify the solving method
Divide $3x^2+6x+2$ by $x^2+3x+2$
Learn how to solve limits by direct substitution problems step by step online.
$\begin{array}{l}\phantom{\phantom{;}x^{2}+3x\phantom{;}+2;}{\phantom{;}3\phantom{;}\phantom{;}}\\\phantom{;}x^{2}+3x\phantom{;}+2\overline{\smash{)}\phantom{;}3x^{2}+6x\phantom{;}+2\phantom{;}\phantom{;}}\\\phantom{\phantom{;}x^{2}+3x\phantom{;}+2;}\underline{-3x^{2}-9x\phantom{;}-6\phantom{;}\phantom{;}}\\\phantom{-3x^{2}-9x\phantom{;}-6\phantom{;}\phantom{;};}-3x\phantom{;}-4\phantom{;}\phantom{;}\\\end{array}$
Learn how to solve limits by direct substitution problems step by step online. Find the integral int((3x^2+6x+2)/(x^2+3x+2))dx. Divide 3x^2+6x+2 by x^2+3x+2. Resulting polynomial. Expand the integral \int\left(3+\frac{-3x-4}{x^2+3x+2}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int3dx results in: 3x.