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Factor the trinomial $x^2-3x-40$ finding two numbers that multiply to form $-40$ and added form $-3$
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$\begin{matrix}\left(5\right)\left(-8\right)=-40\\ \left(5\right)+\left(-8\right)=-3\end{matrix}$
Learn how to solve problems step by step online. Find the integral int((36+2x)/(x^2-3x+-40))dx. Factor the trinomial x^2-3x-40 finding two numbers that multiply to form -40 and added form -3. Thus. Rewrite the fraction \frac{36+2x}{\left(x+5\right)\left(x-8\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B. The first step is to multiply both sides of the equation from the previous step by \left(x+5\right)\left(x-8\right).