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Take out the constant $-1$ from the integral
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$-\int\frac{4+3x^2}{x^3-4x}dx$
Learn how to solve problems step by step online. Find the integral int((-(4+3x^2))/(x^3-4x))dx. Take out the constant -1 from the integral. Rewrite the expression \frac{4+3x^2}{x^3-4x} inside the integral in factored form. Rewrite the fraction \frac{4+3x^2}{x\left(x^2-4\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C. The first step is to multiply both sides of the equation from the previous step by x\left(x^2-4\right).