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Rewrite the fraction $\frac{{\left(-1\right)}^3}{t^{\left(2+3\right)}}$ inside the integral as the product of two functions: ${\left(-1\right)}^3\frac{1}{t^{\left(2+3\right)}}$
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$\int{\left(-1\right)}^3\frac{1}{t^{\left(2+3\right)}}dt$
Learn how to solve problems step by step online. Find the integral int(((-1)^3)/(t^(2+3)))dt. Rewrite the fraction \frac{{\left(-1\right)}^3}{t^{\left(2+3\right)}} inside the integral as the product of two functions: {\left(-1\right)}^3\frac{1}{t^{\left(2+3\right)}}. We can solve the integral \int{\left(-1\right)}^3\frac{1}{t^{\left(2+3\right)}}dt by applying integration by parts method to calculate the integral of the product of two functions, using the following formula. First, identify u and calculate du. Now, identify dv and calculate v.