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Expand the fraction $\frac{x+2}{2x^2-x}$ into $2$ simpler fractions with common denominator $2x^2-x$
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$\int\left(\frac{x}{2x^2-x}+\frac{2}{2x^2-x}\right)dx$
Learn how to solve problems step by step online. Find the integral int((x+2)/(2x^2-x))dx. Expand the fraction \frac{x+2}{2x^2-x} into 2 simpler fractions with common denominator 2x^2-x. Expand the integral \int\left(\frac{x}{2x^2-x}+\frac{2}{2x^2-x}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately. Rewrite the expression \frac{x}{2x^2-x} inside the integral in factored form. We can solve the integral \int\frac{1}{2x-1}dx by applying integration by substitution method (also called U-Substitution). First, we must identify a section within the integral with a new variable (let's call it u), which when substituted makes the integral easier. We see that 2x-1 it's a good candidate for substitution. Let's define a variable u and assign it to the choosen part.