Final Answer
Step-by-step Solution
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We could not solve this problem by using the method: Integrate by partial fractions
Rewrite the integrand $y^3\left(2y^2-3\right)$ in expanded form
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$\int\left(2y^{5}-3y^3\right)dy$
Learn how to solve problems step by step online. Find the integral int(y^3(2y^2-3))dy. Rewrite the integrand y^3\left(2y^2-3\right) in expanded form. Expand the integral \int\left(2y^{5}-3y^3\right)dy into 2 integrals using the sum rule for integrals, to then solve each integral separately. The integral \int2y^{5}dy results in: \frac{1}{3}y^{6}. The integral \int-3y^3dy results in: -\frac{3}{4}y^{4}.