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Rewrite the fraction $\frac{3x^2+1}{\left(x^2-1\right)\left(x^2+6\right)}$ in $2$ simpler fractions using partial fraction decomposition
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$\frac{3x^2+1}{\left(x^2-1\right)\left(x^2+6\right)}=\frac{Ax+B}{x^2-1}+\frac{Cx+D}{x^2+6}$
Learn how to solve problems step by step online. Find the integral int((3x^2+1)/((x^2-1)(x^2+6)))dx. Rewrite the fraction \frac{3x^2+1}{\left(x^2-1\right)\left(x^2+6\right)} in 2 simpler fractions using partial fraction decomposition. Find the values for the unknown coefficients: A, B, C, D. The first step is to multiply both sides of the equation from the previous step by \left(x^2-1\right)\left(x^2+6\right). Multiplying polynomials. Simplifying.