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$\int\frac{y^4-8}{y^3+2y^2}dy$
Learn how to solve integral calculus problems step by step online. Find the integral of (y^4-8)/(y^3+2y^2). Find the integral. Divide y^4-8 by y^3+2y^2. Resulting polynomial. Expand the integral \int\left(y-2+\frac{4y^{2}-8}{y^3+2y^2}\right)dy into 3 integrals using the sum rule for integrals, to then solve each integral separately.