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$\int\frac{x^6+4x^3+4}{x^3-4x^2}dx$
Learn how to solve integral calculus problems step by step online. Find the integral of (x^6+4x^3+4)/(x^3-4x^2). Find the integral. Divide x^6+4x^3+4 by x^3-4x^2. Resulting polynomial. Expand the integral \int\left(x^{3}+4x^{2}+16x+68+\frac{272x^{2}+4}{x^3-4x^2}\right)dx into 5 integrals using the sum rule for integrals, to then solve each integral separately.