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Find the break even points of the polynomial $\frac{\frac{x^3-1}{x^3-2x^2-3x}\left(x+1\right)}{x^2+x-2}+\frac{x^2+x+1}{6x+x^2-x^3}$ by putting it in the form of an equation and then set it equal to zero
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$\frac{\frac{x^3-1}{x^3-2x^2-3x}\left(x+1\right)}{x^2+x-2}+\frac{x^2+x+1}{6x+x^2-x^3}=0$
Learn how to solve problems step by step online. Find the break even points of the expression ((x^3-1)/(x^3-2x^2-3x)(x+1))/(x^2+x+-2)+(x^2+x+1)/(6x+x^2-x^3). Find the break even points of the polynomial \frac{\frac{x^3-1}{x^3-2x^2-3x}\left(x+1\right)}{x^2+x-2}+\frac{x^2+x+1}{6x+x^2-x^3} by putting it in the form of an equation and then set it equal to zero. Multiplying the fraction by x+1. Divide fractions \frac{\frac{\left(x^3-1\right)\left(x+1\right)}{x^3-2x^2-3x}}{x^2+x-2} with Keep, Change, Flip: \frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}. Factor the trinomial \left(x^2+x-2\right) finding two numbers that multiply to form -2 and added form 1.