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$\int\left(\frac{\frac{x^3-1}{x^3-2x^2-3x}\left(x+1\right)}{x^2+x-2}+\frac{x^2+x+1}{6x+x^2-x^3}\right)dx$
Learn how to solve integral calculus problems step by step online. Find the integral of ((x^3-1)/(x^3-2x^2-3x)(x+1))/(x^2+x+-2)+(x^2+x+1)/(6x+x^2-x^3). Find the integral. Simplify the expression inside the integral. The integral \int\frac{\left(x^3-1\right)\left(x+1\right)}{\left(x^3-2x^2-3x\right)\left(x^2+x-2\right)}dx results in: \int\frac{x^3-1}{x\left(x-3\right)\left(x-1\right)\left(x+2\right)}dx. The integral \int\frac{x^2+x+1}{6x+x^2-x^3}dx results in: \frac{1}{6}\ln\left(x\right)-\frac{13}{15}\ln\left(-x+3\right)-\frac{3}{10}\ln\left(x+2\right).