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$\int\frac{x^3+4x^2-10x+7}{x^3-7x-6}dx$
Learn how to solve integral calculus problems step by step online. Find the integral of (x^3+4x^2-10x+7)/(x^3-7x+-6). Find the integral. Divide x^3+4x^2-10x+7 by x^3-7x-6. Resulting polynomial. Expand the integral \int\left(1+\frac{4x^{2}-3x+13}{x^3-7x-6}\right)dx into 2 integrals using the sum rule for integrals, to then solve each integral separately.