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Multiplying the fraction by $8x^3-1$
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$\frac{\frac{\left(x^2-6x+9\right)\left(8x^3-1\right)}{4x^2-1}}{x^2+5x-24}$
Learn how to solve problems step by step online. Factor the expression ((x^2-6x+9)/(4x^2-1)(8x^3-1))/(x^2+5x+-24). Multiplying the fraction by 8x^3-1. Divide fractions \frac{\frac{\left(x^2-6x+9\right)\left(8x^3-1\right)}{4x^2-1}}{x^2+5x-24} with Keep, Change, Flip: \frac{a}{b}\div c=\frac{a}{b}\div\frac{c}{1}=\frac{a}{b}\times\frac{1}{c}=\frac{a}{b\cdot c}. The trinomial \left(x^2-6x+9\right) is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula.