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$\int\frac{\frac{\frac{x^2+5x+6}{x^2-1}\left(x^2+2x-3\right)}{3x+6}\left(x+1\right)}{-x^2+6x-9}dx$
Learn how to solve integral calculus problems step by step online. Find the integral of (((x^2+5x+6)/(x^2-1)(x^2+2x+-3))/(3x+6)(x+1))/(-x^2+6x+-9). Find the integral. Factor the trinomial \left(x^2+2x-3\right) finding two numbers that multiply to form -3 and added form 2. Thus. Rewrite the expression \frac{\frac{\frac{x^2+5x+6}{x^2-1}\left(x-1\right)\left(x+3\right)}{3x+6}\left(x+1\right)}{-x^2+6x-9} inside the integral in factored form.